Find the lengh of the shortest diagonal of this parallelogram

I have a parallelogram with side lengths 1.34 (vertical) and 1.26 (horizontal), I need to find the shortest diagonal and I have no angles just vertices (0,0) (0.6, 1.2) (1.8, 1.6) and (1.2, 0.4)
Please please help!!!!!!!! :) I have no idea what to do

Just about the only way to do this is to draw a Cartesian Coordinate System to determine which diagonals are the shortest. In this case, the end points of the shortest diagonal are (0.6, 1.2) and (1.2, 0.4).

See Diagram: http://i533.photobucket.com/albums/ee339…

x1 = 0.6
y1 = 1.2
x2 = 1.2
y2 = 0.4

d² = (x2 - x1)² + (y2 - y1)²
d² = (1.2 - 0.6)² + (0.4 - 1.2)²
d² = (0.6)² + (- 0.8)²
d² = 0.36 + 0.64
d² = 1
d = √1
d = 1

The length of the shortest diagonal is 1 unit.
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If you plat the points you see (0.6, 1.2) and (1.2, 0.4)
are the closest. then use distance formula

d = sqrt((1.2-0.6)^2 + (0.4-1.2)^2)
d = sqrt(0.6^2 + (-0.8)^2)
=1

I can do this easily, but I need to know: which coordinates are the pair that are the ends of the shorter diagonals?

Use Syllogism