What is the speed of the block 3.70 seconds after it starts moving?
A 4.74 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=10.2 N at an angle θ= 23.0° above the horizontal.
A 4.74 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=10.2 N at an angle θ= 23.0° above the horizontal.
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Horizontal force = F cos θ = 10.2 cos 23 = 9.39 N
Acceleration = force / mass = 9.39 / 4.74 = 1.98 m/s^2
v = at = 1.98*3.7 = 7.33 m /s
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Acceleration = force / mass = 9.39 / 4.74 = 1.98 m/s^2
v = at = 1.98*3.7 = 7.33 m /s
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