Does Power = Current x Voltage? (P=IV?)

I'm revising The National Grid in physics and I'm trying to remember the relevant equation?
I know that they step up voltage to lower current, and therefore reduce energy loss through heat, but what's the equation?
Thanks

Yes, power = current x voltage.

it is also the current squared x resistance ((I^2)xR) where R would be the resistance of the transmission cable. Increasing the voltage allows a lower current for the same power, and the lower current results in less power loss in the cable.

Power is equal to current times resistance but only in a purely resistive circuit, if the circuit has impedance caused by capacitance or inductance, or if the current and voltage are out of phase then it does not and the formula becomes much more complicated.

Yes, power = I*V in Watts. ( = V^2/R = I^2*R). Power is measured in terms of its heating effect.
1 Watt = 1 joule per second. 1 joule = 4.18 calories.
With very high voltages, the current is greatly reduced and I^2*R heating is minimised.

The energy loss across the transmitting wire is I² * Rt or VIt or V*² t /R

However note that the V used here is the potential drop across the transmitting wire and is not the transmitted voltatge from the source.
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E=I*R E=SQR(P*R) E=P/I
R=E/I R=E^2/P R=P/I^2
I=E/R I=SQR(P/R) I=P/E
P=I*E P=I^2*R P=E^2/R

That's all 12 equation.