What is the magnitude of the acceleration of the system
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What is the magnitude of the acceleration of the system

[From: ] [author: ] [Date: 11-12-10] [Hit: ]
8 m/s/s.I originally calculated force of friction, the the weight of the other two blocks, found the net force, and divided it by the total mass of the system, and got 7.......
There is friction between the block and the table.
The suspended 4 kg mass on the left is moving up, the 3 kg mass slides to the right on the table, and the suspended mass 8 kg on the right is moving down. The acceleration of gravity is 9.8 m/s/s.

I originally calculated force of friction, the the weight of the other two blocks, found the net force, and divided it by the total mass of the system, and got 7.56 m/s/s, but it was wrong. What am i doing wrong?

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As a net effect, (8-4)g = 4*g = 39.2 N force is pulling all the masses ( 8+4+3)= 15 kg to the right.

There is an opposing frictional force = μ*3*g= 29.4 μ N

Net force acting on the masses is 39.2 - 29.4 μ

Hence the acceleration is

a = [39.2 - 29.4 μ ] / 15 = (2.613 – 1.960* μ)

Substitute the value of μ and find the answer.
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