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W is a complex cube of unity; show that (a+bw+cw²)/(c+aw+bw²) = w²

[From: ] [author: ] [Date: 11-12-10] [Hit: ]

w^3 = 1
So,
(a+bw+cw²)/(c+aw+bw²)
= w^3(a+bw+cw²)/(c+aw+bw²)
= w^2(aw+bw^2+c)/(c+aw+bw²)
= w^2

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