How to solve... (math/physics question) #4
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How to solve... (math/physics question) #4

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
The first point is at (-16, 0).Since the paper is gridded in squares, a line through the diagonals is 45 degrees.Using the scale, 230 meters is 6.......

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This is not the only way.
You could use components which you mentioned
The thing is that you were asked to use a particular method so I assume that the teacher/prof wants to look at your scale drawing to make sure you know how to do it. Just having the answer wouldn't cut it.

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Get out your graph paper, protractor and ruler and draw the scale drawing.

Using quarter-inch ruled graph paper, and a scale of 10 meters to the quarter-inch, set up the coordinate axes with the cardinal points.

The first point is at (-16, 0).

Since the paper is gridded in squares, a line through the diagonals is 45 degrees. Using the scale, 230 meters is 6.75 inches. Draw a line 6.75 inches long at 45 degrees down to the right (southeast). The second point is 6.75 inches down this line from the first point. It's near (3, - 19), but not quite.

Draw a vertical line through the second point to use as a reference for the 30 degree angle to the third point. Use your protractor to measure 30 degrees to the left of the vertical line (east of north). Using the scale of the drawing, 280 meters is 7 inches. Draw a line 7 inches along the 30 degree heading up to the right (northeast). The third point is at about (16, 6).

Draw in the last segment. Measure its length with your ruler and convert to meters using the scale of the drawing: 1 quarter-inch equals 10 meters.

The heading from the third point back to the origin is some angle of degrees south of west.

Use your protractor to measure the angle, or use the coordinates and the inverse tangent function.
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