A particle on a string at radius r=0.22 m is moving in a (horizontal) circle with angular speed, ω=0.55 rad/s.

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A particle on a string at radius r=0.22 m is moving in a (horizontal) circle with angular speed, ω=0.55 rad/s.

[From: ] [author: ] [Date: 11-08-14] [Hit: ]

ω2 .ω2= 0.55 . 0.22^2 / 0.15^2= 1.......

The string is shortened to 0.15m.Show that the new angular speed is 1.18 rad/s.

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L = m . ω . r^2

If angular momentum is conserved then

m . ω1 . r1^2 = m . ω2 . r2^2

ω2 = 0.55 . 0.22^2 / 0.15^2 = 1.18 rad/s

1

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