Can someone explain the electron configuration of Lawrencium

I am reviewing some chemistry since I'll be starting college this fall and haven't taken it for 3 years. I was going over electron configurations and I never learned how to do the F orbitals. I looked it up, but it didn't make sense to me. For example, the configuration of Lawrencium is [Rn] 5f14 6d1 7s2. Why does it end with 6d1 7s2. Wouldn't 5f14 be the end?

No, because that would give you only 14 more electrons and you need 17 (the difference between LW (103) and Rn (86) ). So you still have the additional 3 electrons: 6d1, 7s2.

named after E O Lawerence - Cal Berkeley Chem prof - GO BEARS!!!!!!!!


it is traditional to WRITE out electron config in terms of NOT energy levels BUT in terms of ascending prinipcle quantum numbers... thus, 5, 6, 7