A 1.50-L sample of a gas at STP has a mass of 4.75 g. What is one possible formula of the gas?
A) NF3
B) CO2
C) C2F4
D) NCl3
E) NO2
A) NF3
B) CO2
C) C2F4
D) NCl3
E) NO2
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1.50L x [1mole / 22.4L] = 0.0670mol of gas.
4.75g / 0.0670 = 70.9g/mole
NF3 = 14 + 3*19 = 71g/mole.
4.75g / 0.0670 = 70.9g/mole
NF3 = 14 + 3*19 = 71g/mole.