How can I find the acceleration of a train

I need to know the forward force in newtons that an actual electric train has. I can't find this value on the internet, so I'm assume the easiest way is to use Fnet = ma. I know the top speed of the train is 80km/h, the mass is 132 tonnes and the engines Horsepower is 4200. If anyone has any idea on how to find the forward force in Newtons that the train has, please say so. Also, if someone knows the force given by a different train that would work too.

The power of engine P = 4200 Hp = 4200 x 745.7 watt = 3.13 MW
--->If W is work --> W = F x S -->P = W/t= (F x S)/t = F x (S/t) --> P = F x v
We found ---> F = P / v = 3.13 x 10^6 / 80 x 1000/3600 = 1.41 x 10^5 N
Acceleleration of the train : a = F/m = 1.41 x 10^5/132 x 10^3 = 1.07 m/s^2

If the power developed by the net force is 4200 Horsepower we can find the net force acting on the train and then find the acceleration of the train. So:

1 horsepower = 750 W (approximately - we will use this value)
Therefore 4200 Horsepower = 4200*750 = 3.15*10^6 W

P= Fnetv

Fnet= P/v
= (3.15*10^6/ 80/3.6)
=141,750 N

a= Fnet/m
= 141,750/(132*10^3)
= 1.07 m/s^2

You have said that is the engines horsepower. Obviously there are actually strong resistive forces that need to be taken into account. Calculating them isn't simple and I wouldn't know how, so I have assumed the 4200 horsepower is the power developed by the net force and that the speed the train is travelling at when it is accelerating at this rate is its top speed. Hope that helps.

To find 'a' you have to know the speed and the time it takes to reach that speed, or the distance covered while reaching that speed.
Then use a = V/t or a = V²/(2x)

Remember too, that Fnet = Feng - Ffriction - Fairdrag; a very complicated calculation.

Further, a constant HP output will result in a decreasing value of Feng for an increasing velocity.