How would I do I find the decelerating distance of Rennata
Favorites|Homepage
Subscriptions | sitemap
HOME > Physics > How would I do I find the decelerating distance of Rennata

How would I do I find the decelerating distance of Rennata

[From: ] [author: ] [Date: 11-06-06] [Hit: ]
d is distance.0 = 25^2 +2*(-1)*d => d = 25^2/2 = 312.d = Vi*t+(1/2)*a*t^2 = 25*25 -0.5(25)^2 = 625 - 625/2 = 312.......
Rennata Gas is driving through town at 25.0 m/s and begins to accelerate at a constant rate of -1.0 m/s2. Eventually Rennata comes to a complete stop.

-
Vf^2=Vi^2+2ad where Vf=0, Vi=25m/s, a = -1m/s^2, d is distance. Plug in the numbers
0 = 25^2 +2*(-1)*d => d = 25^2/2 = 312.5m
Or
Vf = Vi + a*t => 0 = 25 -1*t => t=25s =>
d = Vi*t+(1/2)*a*t^2 = 25*25 -0.5(25)^2 = 625 - 625/2 = 312.5m
1
keywords: of,find,distance,would,How,do,Rennata,decelerating,the,How would I do I find the decelerating distance of Rennata
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .