If an object is submerged in water, on earth, at a depth of 3km, the Pressure on the object is 2.94 x 107 Pa
-
Yes, it is
=>By P = P(atm.) + P(depth)
=>P = 1.01 x 10^5 + hdg
=>P = 1.01 x 10^5 + 3000 x 10^3 x 9.8
=>P = 2.95 x 10^7 Pa
=>By P = P(atm.) + P(depth)
=>P = 1.01 x 10^5 + hdg
=>P = 1.01 x 10^5 + 3000 x 10^3 x 9.8
=>P = 2.95 x 10^7 Pa