mr potato bought a big screen TV. The screen is 52 in. wide and 29 in. high. Find the length of of its diagonal.
a 16 foot ladder is leaned against a wall. if the base of the ladder is 5ft from the wall, how high up on the wall does the ladder reach?
a 16 foot ladder is leaned against a wall. if the base of the ladder is 5ft from the wall, how high up on the wall does the ladder reach?
-
1.) Screen width= a, Screen height= b, Screen diagonal= c.
a(squared) plus b(squared) = c(squared)
52x52 + 29x29 = c(squared)
2704 + 841 = c(squared)
3545 = c(squared)
square root of 3545 = c
c=59.54 inches!
2.) diagonal of ladder = c, base of ladder = a, height of wall= b
c (squared) - a(squared) = b(squared)
16x16 - 5x5 = b(squared)
256 - 25 = b(squared)
231= b(squared)
square root of 231= b
b= 15.2 ft!
a(squared) plus b(squared) = c(squared)
52x52 + 29x29 = c(squared)
2704 + 841 = c(squared)
3545 = c(squared)
square root of 3545 = c
c=59.54 inches!
2.) diagonal of ladder = c, base of ladder = a, height of wall= b
c (squared) - a(squared) = b(squared)
16x16 - 5x5 = b(squared)
256 - 25 = b(squared)
231= b(squared)
square root of 231= b
b= 15.2 ft!