Use the following bond energies to estimate the enthalpy change for the combustion of one mole of methane (CH4). Hint: You should write a balanced equation and Lewis structures.
Bonds Bond Energies in kJ/mol
C-H 414 kJ/mol
O-O 142 kJ/mol
O=O 498 kJ/mol
C=O 736 kJ/mol
C-O 360 kJ/mol
O-H 464 kJ/mol
Enter the answer in kJ
Bonds Bond Energies in kJ/mol
C-H 414 kJ/mol
O-O 142 kJ/mol
O=O 498 kJ/mol
C=O 736 kJ/mol
C-O 360 kJ/mol
O-H 464 kJ/mol
Enter the answer in kJ
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A balanced equation for this process is:
CH4 + 2 O2 ---> CO2 + 2 H2O.
You are breaking:
4 C-H bonds
2 O=O bonds
and forming:
2 C=O bonds
4 H-O bonds
Enthalpy of bonds broken = 4 * 414 + 2 * 498 = 2652 kJ
Enthalpy of bonds formed = 2 * 736 + 4 * 464 = 3328 kJ
Enthalpy change = broken - formed = 2652 - 3328 = -676 kJ per mol CH4
CH4 + 2 O2 ---> CO2 + 2 H2O.
You are breaking:
4 C-H bonds
2 O=O bonds
and forming:
2 C=O bonds
4 H-O bonds
Enthalpy of bonds broken = 4 * 414 + 2 * 498 = 2652 kJ
Enthalpy of bonds formed = 2 * 736 + 4 * 464 = 3328 kJ
Enthalpy change = broken - formed = 2652 - 3328 = -676 kJ per mol CH4