Write
Three times the sum of twice a number and twelve is four times the sum of the number and negative nine.
Three times the sum of twice a number and twelve is four times the sum of the number and negative nine.
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3(2n+12)=4(n-9)
6n+36=4n-36
2n=-72
n = -36
6n+36=4n-36
2n=-72
n = -36
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Let x be the number. Then we can write
3(2x + 12) = 4(x + -9)
6x + 36 = 4x - 36
2x = -72
x = -36
3(2x + 12) = 4(x + -9)
6x + 36 = 4x - 36
2x = -72
x = -36