I'm suppose to find the forumla for the arithmetic sequence.
a(1)=5 a(4)=15
the numbers in (x) are under the a's so its like a exponnet but under if you can know what im saying? :s
the answer was
a(n) =10/3n+5/3
I have no clue how that worked out so if someone can explain much would be appreicated! :)
a(1)=5 a(4)=15
the numbers in (x) are under the a's so its like a exponnet but under if you can know what im saying? :s
the answer was
a(n) =10/3n+5/3
I have no clue how that worked out so if someone can explain much would be appreicated! :)
-
The general formula for the nth term of an arithmetic sequence is (as you should know)
a_n = a_1 + (n - 1)d
where d is the common difference. Using the information you were given,
a_4 = 5 + (4-1)d
15 = 5 + 3d
10 = 3d
10/3 = d
so the formula is
a_n = 5 + (n-1)(10/3)
= 5 + (10/3)(n) - (10/3)
= (10/3)(n) + (5/3)
a_n = a_1 + (n - 1)d
where d is the common difference. Using the information you were given,
a_4 = 5 + (4-1)d
15 = 5 + 3d
10 = 3d
10/3 = d
so the formula is
a_n = 5 + (n-1)(10/3)
= 5 + (10/3)(n) - (10/3)
= (10/3)(n) + (5/3)