Physics Problem involving force

On takeoff, the combined action of the air around the engines and wings of an airplaneexerts an 8983 N force on the plane, directed upward at an angle of 65.6deg above the horizontal. The plane rises with constant velocityin the vertical direction while continuing to accelerate in the horizontal direction.
What is the weight of the plane? The
acceleration due to gravity is 9.8 m/s2
Answer in units of N.

2) What is its horizontal acceleration?
Answer in units of m/s2

If it is traveling at a constant velocity upwards, then the up and down forces have to be equal. The force down is mg, and the force up is 8983sin(65.6deg)

mg = 8983sin(65.6deg) = weight = 8,180.67 N

m = mass = 8983sin(65.6deg) / 9.8 = 834.76 kg

There is only the plane's force in the x direction which is 8983cos(65.6deg) = 3710.92

F = ma so a = F/m = 3710.92 / 834.76 = 4.45 m/s^2

Fv = F * sin(a)
Fv = 8983 * sin(65.6) = W, the weight in Newtons

W = ma
W / 9.8 = m

Fh = F * cos(a)
Fh = 8983 * cos(65.6)

Fh = m * ah
Fh = (W / 9.8) * ah
(8983 * cos(65.6)) = (W / 9.8) * ah
(8983 * cos(65.6)) / (W / 9.8) = ah