. Ms. Ramirez and Mr. Abumoilish are carrying horizontally a uniform ladder of length 6.5[m] and mass of 28[kg].
Mr. A is 1.0[m] from one end, and Ms. R is 2.0[m] from the other end.
Find how much weight [N] is carried by each person.
Mr. A is 1.0[m] from one end, and Ms. R is 2.0[m] from the other end.
Find how much weight [N] is carried by each person.
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Hello
The center of mass of the ladder is in the middle of the ladder, and the distance of the center of mass
to Mr A is 2,25 m, and to Ms R = 1,25 m, and Mr A's distance to Ms R = 3,5 m.
The forces of Mr an Ms on the ladder are up = positive, the force of the center of mass is down and negative.
The sum of the moments around Mr. A is = 0:
- 28*9,81*2,25 + F(R)*3,5 = 0 -->
F(R) (= Ms R) = 28*9,81*2,25/3,5 = 176,58 N
and the moments around Ms R =
- 28*9,81*1,25 + F(A)*3,5 = 0
F(A) (= Mr.A) = 28*9,81*1,25/3,5 = 98,1 N
---------
Together, F(R) + F(A) = 274,68 N (= 28kg*9,81)
Regards
The center of mass of the ladder is in the middle of the ladder, and the distance of the center of mass
to Mr A is 2,25 m, and to Ms R = 1,25 m, and Mr A's distance to Ms R = 3,5 m.
The forces of Mr an Ms on the ladder are up = positive, the force of the center of mass is down and negative.
The sum of the moments around Mr. A is = 0:
- 28*9,81*2,25 + F(R)*3,5 = 0 -->
F(R) (= Ms R) = 28*9,81*2,25/3,5 = 176,58 N
and the moments around Ms R =
- 28*9,81*1,25 + F(A)*3,5 = 0
F(A) (= Mr.A) = 28*9,81*1,25/3,5 = 98,1 N
---------
Together, F(R) + F(A) = 274,68 N (= 28kg*9,81)
Regards