im in grade 9 and our teacher is making us do this question for homework, i have no idea what 2 do
a 1.2x10^3 kg block starting from rest is accelerated by a 2.2x10^3 newton force for a distance of 50meters along a level frictionless surface. what is the final velocity of the object?
a 1.2x10^3 kg block starting from rest is accelerated by a 2.2x10^3 newton force for a distance of 50meters along a level frictionless surface. what is the final velocity of the object?
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Use Newton’s 2nd law to find the acceleration:
ΣF = ma
a = ΣF/m
= 2.2 x 10³N / 1.2 x 10³kg
= 1.8m/s²
The velocity can now be found:
v² = v₀² + 2aΔx
v = √[0 + 2(1.8m/s²)(50m)]
= 13m/s (properly rounded)
Hope this helps.
ΣF = ma
a = ΣF/m
= 2.2 x 10³N / 1.2 x 10³kg
= 1.8m/s²
The velocity can now be found:
v² = v₀² + 2aΔx
v = √[0 + 2(1.8m/s²)(50m)]
= 13m/s (properly rounded)
Hope this helps.
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Work done= 2.2*10^3 * 50 = 1/ m v^2 = 1/2 (1.2 * 10 ^3)*v^2
or, 110= .6*v^2
or v^2= 183.33
or,v= 13.5 m/sec is the answer, I think.
or, 110= .6*v^2
or v^2= 183.33
or,v= 13.5 m/sec is the answer, I think.