Verify that the x-values are solutions of the equation.
1. 2cos(x) - 1 = 0
(a) x = pi/3
(b) x = 5pi/3
can someone please explain how to "verify" please. I understand that you have to make 2cos(x) -1 = 0 into cos(x) = 1/2
which is pi/3 and 5pi/3 but what does it mean verify?? What do I do for (a) and (b)? Thanks.
7 minutes ago - 4 days left to answer.
1. 2cos(x) - 1 = 0
(a) x = pi/3
(b) x = 5pi/3
can someone please explain how to "verify" please. I understand that you have to make 2cos(x) -1 = 0 into cos(x) = 1/2
which is pi/3 and 5pi/3 but what does it mean verify?? What do I do for (a) and (b)? Thanks.
7 minutes ago - 4 days left to answer.
-
verify means to show that it is true
there are 2 parts to this question.
part a, you plug in pi/3 into the equation since x= pi/3 so:
2cos(pi/3) - 1 = 0
2(1/2) - 1 = 0
1 - 1 = 0
0 = 0
you do the same thing for part b but with plugging in 5pi/3 for x
there are 2 parts to this question.
part a, you plug in pi/3 into the equation since x= pi/3 so:
2cos(pi/3) - 1 = 0
2(1/2) - 1 = 0
1 - 1 = 0
0 = 0
you do the same thing for part b but with plugging in 5pi/3 for x
-
Just plug in the values for x into the original equation and see if it holds true:
a) x = pi/3
2cos(x) - 1 = 0
2 * cos(pi/3) - 1 = 0
2 * (1/2) - 1 = 0
1 - 1 = 0
0 = 0
Confirmed
b)
x = 5pi/3
2 * cos(5pi/3) - 1 = 0
You can go from there.
a) x = pi/3
2cos(x) - 1 = 0
2 * cos(pi/3) - 1 = 0
2 * (1/2) - 1 = 0
1 - 1 = 0
0 = 0
Confirmed
b)
x = 5pi/3
2 * cos(5pi/3) - 1 = 0
You can go from there.
-
What value of X, well make cosine equal to (1/2). pi/3 is a 60 degree triangle, and cosine is equal to 1/2 at pi/3, so a is correct. Same with 5pi/3.
-
I'm learning the same stuff, can someone on here please help me with my most! (=
-
I hate math lol