You need to select 3 people from a population who have a particular blood type, where 20% of the population have that blood type. If you select 10 people, what is the probability that at least 3 have
Please walk me through the steps instead of just giving me the answer.-4=.08(w-7)
Divide the .08
50=w-7
Add 7
57=w-4=0.08(w-7)
multiply by 100
400 = 8w -56
add 56
456 = 8w
w = 57-1) divide both s
Thanks in advance for the help :)-To be always negative, the parabola must be open down. So, k
Now apply discriminant, b^2-4ac
4-4k^2
k^2 > 1
Answer: k
Barbara has nickels, dimes, and quarters in her purse worth a total of $2.35. The number of dimes is three less than the sum of the number of nickels and quarters. There are 19 coins altogether. How m
what is the intergral of (0.5) / (x + 1) ??
i understand it would be .5 ln (x + 1).
alternatively.... isnt (.5) / (x+ 1) the same as 1 / (2x + 2)???? correct me if i am wrong, but isnt the intergral
Bounded region D={(x,y): 0
f(x,y)= 3xy + 2cos(x)
How do you find the abs. max and min values for the above function?-First, we find the critical point inside D.
f_x = 3y - 2 sin x, f_y = 3x.
Settin
I have to prove:
(1-sin^2xcsc^2x +sin^2x)/cos^2x = tan^2x
Every time I solve it i get it equal to tan^2x + 1
Could someone help me, any help would be appreciated thanks!-Well the csc^2(x) can be m
to hit a target a meters above the ground and b meters from the origin, where it is being fired from (ground level). Im given the initial velocity, but not the angle. I can see that the problem can be
The derivative of secx is secxtanx.
The derivative of cotx is -(cscx)^2-d/dx(4 sec(x) tan(x)-csc^2(x)-4 sec(x)-cot(x)) = (2 cot(x)+1) csc^2(x)-2 sec^3(x) (sin(2 x)+cos(2 x)-3)
Possible derivation:
d/
I honestly dont get it... how would you do this?
Please no deritives or whatever its called because I havent learned it yet-14700+.5x=-35x
35.5x=-14700
x=-414,08
1/x=-1/414.08
~David
...the inverse for the function:y= (x^2 +1) / (2x -5)
Ive been stuck on this question for days, i cant even find the inverse of this equation >_-Domain is all possible x values in a function.
Range
I dont like using x as the dummy variable for f^-1, particularly when the domain and range of f are not the same.f has the domain x>2, and the range f(x)>0.Write this as:
y = f(x) = sqrt(1/(x - 2)) .
what is the intergral of (0.5) / (x + 1) ??
i understand it would be .5 ln (x + 1).
alternatively.... isnt (.5) / (x+ 1) the same as 1 / (2x + 2)???? correct me if i am wrong, but isnt the intergral
f(x,y,z)=sqrt(x+y+z)
P=(2,1,1)
u=
How do you find the rate of change of f at P in the direction of the vector u?-You should have this equation already.∇f ⋅ û
====
You do need to know u.
| ∇f(P) | i
