general quadratic equation
ax^2 + bx + c = 0. From that,
x = [ - b ± √(b^2 - 4ac) ] / 2a
So in problem 1, a = 7, b = - 48, and c = - 7.
Now just plug in and compute!
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Rory say: Easy. For number 1, A=7 B=-48 C=-7. For number 2, A=9 B=-15 C=4. For number 3, A=25 B=10 and C=1. Use these to set up your quadratic to get your v h and x
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Michael say: Well,
3.
25x² + 10x + 1 = 0
is equivalent to :
(5x)² + 2 * 5x * 1 + 1² = 0
(5x + 1)² = 0
5x + 1 = 0
x = -1/5
one at a time
hope it' ll help !!
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cidyah say: 3.
25x^2+10x+1=0
This equation is of form ax^2+bx+c=0
a = 25 b = 10 c = 1
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-10 +/-sqrt(10^2-4(25)(1)]/(2)(25)
discriminant is b^2-4ac =0
x=[-10 +√(0)] / (2)(25)
x=[-10 -√(0)] / (2)(25)
x=[-10+0] / 50
x=[-10-0] / 50
x=-1/5, -1/5
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