Please somebody help me before I cry?

multiply 1st by - 3 and add result to the 2nd , solve for y ; then x..NOT HARD

Make the coefficient of one of the variables the same in both equations.
One way to do this is to multiply both sides of the first equation by 3.
9x - 15y = 3

Subtract one equation from the other.
(9x + 20y) - (9x - 15y) = 10 - 3

Simplify to solve for one variable
35y = 7
y = 1/5

Use this result to solve the other variable.

3x-5y=1 | x3 | 9x-15y=3
9x+20y=10 | x1 | 9x-20y=10
________________________ -

-35y = -7
y = 1/5

3x-5(1/5) = 1
3x-1=1
3x=2
x=2/3

so x=2/3 and y = 1/5

3x-5y=1
In order to get the 3x by itself you have to add 5y to each part of the first equation. You get:
3x=1+5y
If 3x=1+5y then 9x=3+15y (must multiply both sides of the equation.
Now substitute 3+15y in the 2nd equation.
3+15y+20y=10 If you get the y on one side and the numbers on the other you get:
15y+20y=10-3 or
35y=7 divide both sides by 35
y=7/35 or y=1/5
Then if you substitute 1/5 for y you get:
3x-5(1/5)=1 simplify 1 x 1/5
3x-1=1 add 1 to each side
3x=2 Divide each side by 3 to solve x
x=2/3