The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form
L(t) = 200 (1 - 0.95e^-0.19t)
At what age would you expect the halibut to be 120 cm long?
Please explain your process because this is the 3rd part of the problem and I tried doing it but I don't really get the use of ln (natural logs) because I feel like I'll have to use natural log here? Please explain your steps! Thank you~!
L(t) = 200 (1 - 0.95e^-0.19t)
At what age would you expect the halibut to be 120 cm long?
Please explain your process because this is the 3rd part of the problem and I tried doing it but I don't really get the use of ln (natural logs) because I feel like I'll have to use natural log here? Please explain your steps! Thank you~!
-
L(t) = 200 (1 - 0.95e^-0.19t) = 120 cm
OR,
1 - 0.95e^-0.19t = 120/200 = 0.6,
OR,
0.95e^-0.19t = 1 -0.6 = 0.4,
OR,
e^-0.19t = 0.4/0.95 = 0.4211,
OR,
e^0.19t = 1/0.4211 = 2.375,
OR,
0.19t = ln(2.375) = 0.865,
OR,
t = 4.553 time-units >==========================< ANSWER
OR,
1 - 0.95e^-0.19t = 120/200 = 0.6,
OR,
0.95e^-0.19t = 1 -0.6 = 0.4,
OR,
e^-0.19t = 0.4/0.95 = 0.4211,
OR,
e^0.19t = 1/0.4211 = 2.375,
OR,
0.19t = ln(2.375) = 0.865,
OR,
t = 4.553 time-units >==========================< ANSWER