1. Indicate in standard form the equation of the line passing through the given points.
S(.5, 1), T(.5, 4)
a. x = 1/2
b. y = 1/2
c. -2x + y = 0
2. Find the equation of a line, in slope-intercept form of a line that passes through the point (-5, -1) and is parallel to the line -2x + 4y = 8.
a. y = 1/2x + 3/2
b. y= 1/2x - 3/2
c. y= -1/2x - 7/2
d. y= -1/2x + 13/2
3. Find the equation of a line, in slope-intercept form of a line that passes through the point (-5, -1) and is parallel to the line -2x + 4y = 8.
a. y = 1/2x + 3/2
b. y= 1/2x - 3/2
c. y= -1/2x - 7/2
d. y= -1/2x + 13/2
Please Help! I'm stuck on these 3!
S(.5, 1), T(.5, 4)
a. x = 1/2
b. y = 1/2
c. -2x + y = 0
2. Find the equation of a line, in slope-intercept form of a line that passes through the point (-5, -1) and is parallel to the line -2x + 4y = 8.
a. y = 1/2x + 3/2
b. y= 1/2x - 3/2
c. y= -1/2x - 7/2
d. y= -1/2x + 13/2
3. Find the equation of a line, in slope-intercept form of a line that passes through the point (-5, -1) and is parallel to the line -2x + 4y = 8.
a. y = 1/2x + 3/2
b. y= 1/2x - 3/2
c. y= -1/2x - 7/2
d. y= -1/2x + 13/2
Please Help! I'm stuck on these 3!
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1) S(1/2, 1) , T(1/2, 4) => notice that the x-coordinates are the same the line therefore is vertical:
x = 1/2
a => answer
2) -2x + 4y = 8
4y = 2x + 8
y = 1/2*x + 2
m = 1/2 => parallel lines have the same slope, then:
y - y₁ = m(x - x₁)
y + 1 = 1/2(x + 5)
y = 1/2*x + 3/2
a => answer
3) same as 2
x = 1/2
a => answer
2) -2x + 4y = 8
4y = 2x + 8
y = 1/2*x + 2
m = 1/2 => parallel lines have the same slope, then:
y - y₁ = m(x - x₁)
y + 1 = 1/2(x + 5)
y = 1/2*x + 3/2
a => answer
3) same as 2
-
step by step solutions:
1. x = 1/2
http://symbolab.com/solver/line-calculat...
2. a. y = 1/2x + 3/2
http://symbolab.com/solver/parallel-line...
3. same questions as 2
hope this helps
1. x = 1/2
http://symbolab.com/solver/line-calculat...
2. a. y = 1/2x + 3/2
http://symbolab.com/solver/parallel-line...
3. same questions as 2
hope this helps