what is the derivative of
(x-2)-(sin2x/4)
2csc^3(sqrt(x))
I got -3cscxcotx/(sqrt(x))-which I know is wrong
cos^3(5x^2-6)
I got 30cos^2(5x^2-6)(-sin(5x^2-6)) --which I know is wrong too.
Thanks for the help
(x-2)-(sin2x/4)
2csc^3(sqrt(x))
I got -3cscxcotx/(sqrt(x))-which I know is wrong
cos^3(5x^2-6)
I got 30cos^2(5x^2-6)(-sin(5x^2-6)) --which I know is wrong too.
Thanks for the help
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1/
y ' = 1 - (2/4)cos(2x) = 1 - (cos(2x))/2
2/
Chain rule
with u = sqrt(x)
---> y ' = -6csc^3x cotx (1/(2 sqrtx)) = ...simplify
3/
Chain rule
---> y ' = -30xcos^2(5x^2-6) sin(5x^2-6)
y ' = 1 - (2/4)cos(2x) = 1 - (cos(2x))/2
2/
Chain rule
with u = sqrt(x)
---> y ' = -6csc^3x cotx (1/(2 sqrtx)) = ...simplify
3/
Chain rule
---> y ' = -30xcos^2(5x^2-6) sin(5x^2-6)
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3) 30x cos^2(5x^2-6) sin(6-5x^2)
changing the sign of the argument of sin() absorbs the preceding minus sign
changing the sign of the argument of sin() absorbs the preceding minus sign
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full step by step solution
http://symbolab.com/solutions/derivative…
good luck
http://symbolab.com/solutions/derivative…
good luck