How to find the Derivative
Favorites|Homepage
Subscriptions | sitemap
HOME > > How to find the Derivative

How to find the Derivative

[From: ] [author: ] [Date: 13-09-28] [Hit: ]
......
what is the derivative of

(x-2)-(sin2x/4)

2csc^3(sqrt(x))

I got -3cscxcotx/(sqrt(x))-which I know is wrong

cos^3(5x^2-6)

I got 30cos^2(5x^2-6)(-sin(5x^2-6)) --which I know is wrong too.

Thanks for the help

-
1/
y ' = 1 - (2/4)cos(2x) = 1 - (cos(2x))/2
2/
Chain rule
with u = sqrt(x)
---> y ' = -6csc^3x cotx (1/(2 sqrtx)) = ...simplify

3/
Chain rule
---> y ' = -30xcos^2(5x^2-6) sin(5x^2-6)

-
3) 30x cos^2(5x^2-6) sin(6-5x^2)
changing the sign of the argument of sin() absorbs the preceding minus sign

-
full step by step solution

http://symbolab.com/solutions/derivative…

good luck
1
keywords: to,the,How,Derivative,find,How to find the Derivative
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .