Question on limits on factorial
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Question on limits on factorial

[From: ] [author: ] [Date: 13-08-22] [Hit: ]
When the denominator approaches ∞ more rapidly than the numerator, the limit as n approaches ∞ is 0.-Hint: (n+2)! = (n+2)(n+1)n!......
lim(n→∞) [n!/(n+2)!]

how can I solve this? Can someone guides me? Thanks!

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(n+2)! = n! * (n+1) * (n+2)

so n!/(n+2)! simplifies to 1/[(n+1)(n+2)]

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The denominator approaches ∞ much faster than the numerator does. Because of that, as n approaches ∞ in both cases, the denominator will end up exponentially higher.

When the denominator approaches ∞ more rapidly than the numerator, the limit as n approaches ∞ is 0.

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Hint: (n+2)! = (n+2)(n+1)n!
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