How to compute this derivative z = w^1/3 + w^2/3

[From: ] [author: ] [Date: 13-08-18] [Hit: ]

z = w^1/3 + w^2/3 using Leibniz notation?

Also dz/dw____w = -1.

Any help is appreciated.

dz = (1/3*w^(-2/3) + 2/3*w^(-1/3)) dw

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