Use the intercepts and symmetry to sketch the graph of the equation.
y = x^3 - 1
y = x^3 - 1
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When x = 0, y = 0 - 1 = -1 so the y-intercept is (0, -1).
When y = 0, 0 = x³ - 1 so x³ = 1, so x = 1.
There is a single x-intercept at (1, 0).
Sketch the usual cubic shaped graph passing through (0, -1) and (1, 0).
Alternatively, just take the simple cubic graph for y = x³ and translate it down one unit.
When y = 0, 0 = x³ - 1 so x³ = 1, so x = 1.
There is a single x-intercept at (1, 0).
Sketch the usual cubic shaped graph passing through (0, -1) and (1, 0).
Alternatively, just take the simple cubic graph for y = x³ and translate it down one unit.