please explain your steps :)
Thank you!
Thank you!
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This is a difference of two squares. The correct way to write the problem is 1/36 - x^2. Recall that the rule for factoring a difference of two squares a^2 - b^2 = (a - b)(a + b). So you need to take the positive square root of a^2, which is a, and the positive square root of b^2, which is b.
Here, the square root of 1/36 is 1/6 and the square root of x^2 is x. So now use the factoring rule mentioned above. FOIL your answer to check it.
Here, the square root of 1/36 is 1/6 and the square root of x^2 is x. So now use the factoring rule mentioned above. FOIL your answer to check it.
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The difference of two squares is equal to the product of the sum and difference of the square root of the two squares. In general,
a² - b² = (a + b)(a - b)
Therefore,
1/36 - x² = (1/6 + x)(1/6 - x)
a² - b² = (a + b)(a - b)
Therefore,
1/36 - x² = (1/6 + x)(1/6 - x)
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1/36 - x^2 is the difference of two squares. All problems like this are factored as follows:
a^2 - b^2 = (a + b)(a - b)
1/36 - x^2 = (1/6 + x)(1/6 - x)
a^2 - b^2 = (a + b)(a - b)
1/36 - x^2 = (1/6 + x)(1/6 - x)
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1/36-x2=
use this formula a2-b2=(a+b)(a-b)
1/36-x2=(1/6)2-x2
=(1/6-x)(1/6+x)=0
1/6-x=0
x=1/6
1/6+x=0
x=-1/6
factors are=1/6 and -1/6
use this formula a2-b2=(a+b)(a-b)
1/36-x2=(1/6)2-x2
=(1/6-x)(1/6+x)=0
1/6-x=0
x=1/6
1/6+x=0
x=-1/6
factors are=1/6 and -1/6
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= 1/(6 - x) * 1/(6 + x)