a 1 ohm resistor is connected in paralle with a d'Arsonval movement having a full scale deflection of 1 mA.
if a 40 mA current produces a deflection that is 80% of full scale , determine the resistance of the d'Arsonval movement
thanks in advance
if a 40 mA current produces a deflection that is 80% of full scale , determine the resistance of the d'Arsonval movement
thanks in advance
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80% of 1 mA = 0.8mA of current through the meter
40mA - 0.8mA = 39.9mA flows through the 1 ohm resistor
Voltage developed then is 39.9 mA * 1 Ohm = 39.2 mV
d'Arsonval resistance then = 39.2 mV / 0.8 mA = 49 ohms
Hope this helps,
Newton1Law
40mA - 0.8mA = 39.9mA flows through the 1 ohm resistor
Voltage developed then is 39.9 mA * 1 Ohm = 39.2 mV
d'Arsonval resistance then = 39.2 mV / 0.8 mA = 49 ohms
Hope this helps,
Newton1Law
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Jsj