Equation of tangent line help

Find the equation of the tangent line to the curve y = sqrt (1 + 4sinx) at the point (0,1). Please show steps, thank you!

dy/dx = 1/2*(4*cos(x)) * (1 + 4sin(x))^(-1/2) = 2cos(x)/√(1 + 4sin(x))

Slope of tangent line at (0,1) = 2

Eqn of tangent line:

y - 1 = 2x => y = 2x + 1