I need help with algebra 1!!

1. The vertex of a quadratic function is in the second quadrant. The related equation has no real solutions. Which statement is TRUE?
A. The graphics opens down
B. The graphics opens up
C. The y-intercept is 0
D. The axis of symmetry is x=0

2.What are the solutions of x to the second power - 2x - 3 = 0
A.-1 &3
B -1 &-3
C 1 & -3
D 1 & 3

3. What are the solutions of (x+2)(x-3)=0 ?
A.2 & -3
B -2 & -3
C -2 & 3
D 2 & 3

1) if the vertex is in Quadrant II then the y will be positive and x will be negative. if the equation has no real solution that means it does not touch nor cross the x axis. so the parabola must open upwards.
so B

2) x^2 - 2x -3 =0
=> x^2 + x - 3x -3 = 0
=> x(x +1) -3(x +1) = 0
=> (x +1)(x -3) = 0
=> x + 1 = 0 and x -3 = 0
=> x = -1 and x = 3
so A

3) (x+2)(x-3)=0
=> x + 2 = 0 and x -3 = 0
=> x = -2 and x = 3
so C

1. B
2. A
3. C

1 : im not sure
2: c
3: a

Dear algebra, we don't know where your X went, she isn't comming back... We don't know Y either.

im not shure about #1
#2 is a
#3 is c