Logarithms: Solve the equation
Favorites|Homepage
Subscriptions | sitemap
HOME > > Logarithms: Solve the equation

Logarithms: Solve the equation

[From: ] [author: ] [Date: 13-04-02] [Hit: ]
so a= (-7+/-root of 141/)2 so your values will be a=2.4 and a=9.3^x=2.4 and 3^x=9.apply logs on both sides for each equation u will get x=log2.and x= log 9.......
I need help on this question.

9^x + 7(3^x-1) = 16

Thanks in advance.

-
make 9^x= 3^2x and substitute 3^x = a
then equation will be a^2+7(a-1)=16
a^2+7a-7=16
a^2+7a-23=0
so a= (-7+/-root of 141/)2 so your values will be a=2.4 and a=9.43
3^x=2.4 and 3^x=9.43
apply logs on both sides for each equation u will get x=log2.4 to the base 3
and x= log 9.43 to the base 3
1
keywords: equation,the,Logarithms,Solve,Logarithms: Solve the equation
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .