I don't even think this is meant to be a hard question, but I can't figure out how to solve it.....
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OK, that can be done! :)
This is just like adding two fractions and expressing in simplest form (reduced form).
The LCD here is x(x+3) so multiply the first term by (x+3)/(x+3) and the second term by x/x.
That will give you:
(x+3)/x(x+3) + x/x(x+3)
Now they have the same denominator so you can add the numerators to get
(2x + 3) / x(x+3)
And that is the final answer, in simplest form.
:)
This is just like adding two fractions and expressing in simplest form (reduced form).
The LCD here is x(x+3) so multiply the first term by (x+3)/(x+3) and the second term by x/x.
That will give you:
(x+3)/x(x+3) + x/x(x+3)
Now they have the same denominator so you can add the numerators to get
(2x + 3) / x(x+3)
And that is the final answer, in simplest form.
:)
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(1/x) + (1/(x+3))
equate the denominator,
= (1/x)((x+3)/(x+3)) + (1/(x+3))(x/x)
= (x+3)/(x(x+3)) + x/(x(x+3))
= ((x+3)+x)/(x(x+3))
= (2x+3)/(x(x+3))
equate the denominator,
= (1/x)((x+3)/(x+3)) + (1/(x+3))(x/x)
= (x+3)/(x(x+3)) + x/(x(x+3))
= ((x+3)+x)/(x(x+3))
= (2x+3)/(x(x+3))
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You need to cross multiply the denominators with the numeraters, then you can isolate x, and find it.