....If a dart is thrown inside the square, what is the probability that it lands inside the circle? Round to nearest percent.
Thank you.
Thank you.
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Don't know if this is the right solution but I hope it helps
Area of square 12*12=144
Area of circle r²*pi =113
Divide 113/144=79% it lands in circle
21% out of circle.
Area of square 12*12=144
Area of circle r²*pi =113
Divide 113/144=79% it lands in circle
21% out of circle.
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Area of square = 12*12 = 144 in^2
Area of circle = 36pi
Area of square outside of circle =
(144-36pi)
P of landing outside circle = (144-36pi)/144
P of landing inside circle = 1 - (144-36pi)/144
P = (144-144+36pi)/144
P = pi/4 = 0.7854
P = 79%
Area of circle = 36pi
Area of square outside of circle =
(144-36pi)
P of landing outside circle = (144-36pi)/144
P of landing inside circle = 1 - (144-36pi)/144
P = (144-144+36pi)/144
P = pi/4 = 0.7854
P = 79%
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so you need to find the area of the square and the area of the circle
S = s^2 = (2*6)^2 = 144
C = pi*r^2 = 36pi
36pi / 144 = .785
79%
S = s^2 = (2*6)^2 = 144
C = pi*r^2 = 36pi
36pi / 144 = .785
79%