Given that f(x) = -3x^2 + 6 and g(x) = 4x – 8,?
find : f(-2) – g(4).
g(4) – f(-2)
f(-2) + f(3)
g(3) + g(-4)
find : f(-2) – g(4).
g(4) – f(-2)
f(-2) + f(3)
g(3) + g(-4)
-
Given that f(x) = -3x^2 + 6 and g(x) = 4x – 8,?
find : f(-2) – g(4)=-3(-2)^2 - (16-8)=-12-8=-20
g(4) – f(-2)
=(16-8)-(-12)=8+12=20
f(-2) + f(3)
=-3(4)+12-8
=-8
g(3) + g(-4)
=4(3)-8+(-16-8)
=12-8-24
=-20
find : f(-2) – g(4)=-3(-2)^2 - (16-8)=-12-8=-20
g(4) – f(-2)
=(16-8)-(-12)=8+12=20
f(-2) + f(3)
=-3(4)+12-8
=-8
g(3) + g(-4)
=4(3)-8+(-16-8)
=12-8-24
=-20