need it explained step by step
thank you in advance
thank you in advance
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sqrt(250x^16) / sqrt(2x)
You have to find the square root of each. They do not cancel eachother out. So, you really do have to find the sqrt of 250, the sqrt of x^16, and the sqrt of 2x
A trick to remember here is when finding a root of something that is "to the power of," you subtract the root value (2) from the powers.
I suggest the factoring method 250=5*5*5*2
So the top is sqrt[ (5^3)(2)(x^16) ], which is (5^(3-2)) (sqrt2)(x^(16-2))
This is simplified to (5)(sqrt2)(x^14).
Your problem is now [5sqrt(2)x^14]/sqrt(2x)
You have to find the square root of each. They do not cancel eachother out. So, you really do have to find the sqrt of 250, the sqrt of x^16, and the sqrt of 2x
A trick to remember here is when finding a root of something that is "to the power of," you subtract the root value (2) from the powers.
I suggest the factoring method 250=5*5*5*2
So the top is sqrt[ (5^3)(2)(x^16) ], which is (5^(3-2)) (sqrt2)(x^(16-2))
This is simplified to (5)(sqrt2)(x^14).
Your problem is now [5sqrt(2)x^14]/sqrt(2x)
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Step1: Both the sqrt gets cancelled out, remaining: 250x^16/2x
Step2: divide 250 by 2 and divide 2 by 2, remaining: 125x^16/1x or simply 125x^16/x
Step3: divide top by x and bottom by x, remaining: 125x^15
Step2: divide 250 by 2 and divide 2 by 2, remaining: 125x^16/1x or simply 125x^16/x
Step3: divide top by x and bottom by x, remaining: 125x^15