An ideal power transformer has a primary winding of 110 turns and a secondary winding of 22 turns.

a. Calculate the secondary voltage if 1100 V is applied to the primary.

b. If a resistance of 20 ohms is connected across the secondary winding of the transformer, calculate the primary and the secondary currents.

c. Prove that the input power is equal to the output power.

a.
Vs = (22/110)*(1,100V) = 220 Volts

b.
Is = Vs/Rs = 220V/20 Ohm = 11 Amps
Ip = (22/110)*(11A) = 2.2 Amps

c.
Pin = (Vp)*(Ip)I = (1,100)*(2.2A) = 2,420 Watts
Pout = Vs)*(Is) = (220V)*(11A) = 2,420 Watts

a) 22*1100/110=220
b) Is=220/20=11. Ip=Is/5=2.2
c) No proof is required, because this is the definition. There are no losses in an ideal transformer.