Determine the domain of f(x)= 1/(√(4x-(3x^2)))
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Determine the domain of f(x)= 1/(√(4x-(3x^2)))

[From: ] [author: ] [Date: 12-09-13] [Hit: ]
which is also undefined.So to be included in the domain, the value under the radical must be positive.This has two roots, x = 0, and x = 4/3.......
HELP PLEASE so confuzed

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The domain is anywhere the function is defined.
In this case, in order to be included in the domain, what's under the radical must be zero or positive.
But also realize that if what's under the radical is zero, then the denominator is equal to zero, which is also undefined.
So to be included in the domain, the value under the radical must be positive.

(4x - 3x^2) > 0
x(4 - 3x) > 0

This has two roots, x = 0, and x = 4/3.
values between these, such as x = 1, are included in the domain because 4x - 3x^2 is positive for x = 1.
So the range of acceptable values is (0, 4/3) exclusive (meaning the endpoints are not included).

Domain = 0 < x < 4/3

Hope this helps.
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