If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations.
x – y + 2z = –2
2x + 2y + z = 7
3x + 3y – z = 3
A.) 2x + 2y = 7
3x + 3y = 3
B.) 2x + 2y = 7
5x + 5y = 10
C.) 7x + 5y = 4
3x + 3y = 3
D.) 7x + 5y = 4
5x + 5y = 10
I know this question looks really long but I have 10 more of these problems to do and I have no idea how to do them. If you could please help me I'd really appreciate it and I will pick a best answer to give 10 points to. Thank you so much in advance!!!
x – y + 2z = –2
2x + 2y + z = 7
3x + 3y – z = 3
A.) 2x + 2y = 7
3x + 3y = 3
B.) 2x + 2y = 7
5x + 5y = 10
C.) 7x + 5y = 4
3x + 3y = 3
D.) 7x + 5y = 4
5x + 5y = 10
I know this question looks really long but I have 10 more of these problems to do and I have no idea how to do them. If you could please help me I'd really appreciate it and I will pick a best answer to give 10 points to. Thank you so much in advance!!!
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for first and third, you multiple the third equation by 2 so you get
6x + 6y - 2z = 6 then add it to the first equation
7x + 5y = 4
the second one you just add second + third
5x + 5y = 10
so the answer is D :D
6x + 6y - 2z = 6 then add it to the first equation
7x + 5y = 4
the second one you just add second + third
5x + 5y = 10
so the answer is D :D