Substitution Integral Math question
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Substitution Integral Math question

[From: ] [author: ] [Date: 12-08-09] [Hit: ]
-Its because ∫1/(3 - x) dx first integrates to -ln|3 - x| (Do you understand that part?Remember that ln(1) = 0, so youre just left with ln(5).-No problem at all =).......
Hi I got an explanation for this before but am still confused, can someone help with steps its problem A17 : http://www.baruch.cuny.edu/sacc/documents/MTH2205_FinalExamv8.pdf.
the persons said -ln 1 + ln 5 = ln 5 but I don't get how this happens.

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It's because ∫1/(3 - x) dx first integrates to -ln|3 - x| (Do you understand that part?)

Now plug in those limits that you wanted:

-ln|3 - x| evaluated from -2 to 2

= -ln(1) + ln(3 - (-2)) = -ln(1) + ln(5)

Remember that ln(1) = 0, so you're just left with ln(5).

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No problem at all =).

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