Which Quantum Numbers never occur for ground state Se?
Using the notation n, l ml, ms, which of the following combinations of quantum numbers never occurs
for any electron in a ground state Se atom?
A) 4,2, +1, +1/2
B) 2,0,0, -1/2
C) 2,1,0,-1/2
D) 4; 1,0,-1/2
E) 3,2, -2, +1/2
Ok so we know that Se last valence e- is in the 4P8... first all of these look possible. I hazzard to guess that it is E...
When N=3 if L=2 (this would correspond to sub-shells D right?) So if/when N=3 there is no electron in the D shells???
I had another question like this a while ago and I keep getting confused by the statement L=N-1 because, as i ask above, yes its a correct seeries of numbers according to the little formula but it doesn't happen. So why on earth does that formula make it sound possible?
Using the notation n, l ml, ms, which of the following combinations of quantum numbers never occurs
for any electron in a ground state Se atom?
A) 4,2, +1, +1/2
B) 2,0,0, -1/2
C) 2,1,0,-1/2
D) 4; 1,0,-1/2
E) 3,2, -2, +1/2
Ok so we know that Se last valence e- is in the 4P8... first all of these look possible. I hazzard to guess that it is E...
When N=3 if L=2 (this would correspond to sub-shells D right?) So if/when N=3 there is no electron in the D shells???
I had another question like this a while ago and I keep getting confused by the statement L=N-1 because, as i ask above, yes its a correct seeries of numbers according to the little formula but it doesn't happen. So why on earth does that formula make it sound possible?
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hello again .....how are you ??
A) is wrong
because as you said its valence electron configuration is 4s2 4p4......4p means n = 4 and l = 1
but A corresponds to 4d as l = 2 mens 4d subshell
E is correct Se has 3d electrons but no 4d
feel free to ask any questions
A) is wrong
because as you said its valence electron configuration is 4s2 4p4......4p means n = 4 and l = 1
but A corresponds to 4d as l = 2 mens 4d subshell
E is correct Se has 3d electrons but no 4d
feel free to ask any questions