Given the following coordinates use slope to classify the triangle--is it a right triangle

A (-6, 3)
B (-2, -2)
C (3, 2)

find the slope between a&b, a&c, and b&c.

a&b : (3-(-2))/(-6-(-2) = 5/-4 = -5/4
a&c : (3-2)/(-6-(-3)) = 1 / -3 = -1/3
b&c : (-2-2)/(-2-3) = -4/-5 = 4/5

Remember that two lines are perpendicular if their slopes are opposite in sign and reciprocals. -5/4 and 4/5 are perpendicular lines, so this is a right triangle.

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