Help with Math please show work so i can figure this out for myself

Solve this equation by using the quadratic formula. Reduce in terms of radicals and fractions. Show answer as a decimal.

3x^2-8x+2=0

Thank you very much

What does quadratic formula do? It shows you solutions to quadratic equation.
Take a quadratic equation
ax^2 + bx + c = 0

In your equation a=3, b=-8 and c=2.

First there is a number (called discriminant, D) that is b^2-4ac. If it is larger than zero, there are two real solutions. If it is smaller, there are no real solutions (if equal, there is one solution).

Here it is 40. That means there are two solutions.
First one is (-b+sqrt(D))/2a
That is (8+sqrt(40))/6.
The other one is (-b-sqrt(D))/2a
That is (8-sqrt(40))/6.

We can do a little more. We notice that 40=2*2*2*5. Therefore sqrt(40) = sqrt(4)*sqrt(10)= 2*sqrt(10)
So (8+sqrt(40))/6 = ( 8+2sqrt(10) )/6 = ( 4+sqrt(10) )/3. Similar for the other solution.


To see answer as decimal, just plug it into calculator.

You can also use Wolfram Alpha: https://www.wolframalpha.com/input/?i=3x…

Edit: I had stupid error there. Hope it is correct now.

First make your equation "look like" this one, and then you will know what the values of a, b, and c will be, in the quadratic equation.

ax^2 + bx + c = 0

3x^2 -8x+ 2 = 0

Your equation is already in the right format, so, a = 3, b = -8, and c = 2.

The discriminant, b^2-4ac, = (-8)^2 - 4*3*2 = 64 - 24 = 40.

[-b +- sqrt(b^2 - 4ac) ] / 2a
= [-(-8) + sqrt(40) ] / 2(3) and = [-(-8) - sqrt(40) ] / 2(3)
= [ 8 + 2*sqrt(10) ] / 6 and [ 8 - 2*sqrt(10) ] / 6

See the website below:

http://www.mathway.com/

You can enter your math problems and get the answers to them but if you want to view the steps you have to sign up and pay some money. I hope that I helped! :)