Highly difficult problem on laws of cosines

The question -printed-:

A helicopter spots two possible landing sites at the top and bottom of an 11 degree incline. The distance between the sites is 500 m, and the helicopter is 85 m directly above the midpoint of the segment joining them. How far is the helicopter on a direct line from each site?

What I want:

1) graph of that shape
2) The answers with steps and complete explanation
3) Link explaining problems as this one.

And thank you all very much.

I've provided a picture I gathered from your words. I didn't place the 500m distance on the picture itself, but it is the sloped hypotenuse between points A and B. Just so you know. So see the link below.

From that graph you can see that the distance from the helicopter (85m above the midpoint) to A is (from Pythagorean's theorem):

    √[(85m + ½⋅500m⋅ sin(11°))²+ (½⋅500m⋅ cos(11°))²]

or,

     ≈ 278.988m

Also from that graph you can see that the distance from the helicopter (85m above the midpoint) to B is:

    √[(85m - ½⋅500m⋅ sin(11°))²+ (½⋅500m⋅ cos(11°))²]

or,

     ≈ 248.225m

Hopefully, the picture is sufficiently explanatory that you can match up the pieces I provided with the problem statement you wrote out and can follow the logic there and here. You need to know that:

    x = r ⋅ cos θ
    y = r ⋅ sin θ

But I suspect you do.