Can u answer this problem

One day, a person went to horse racing area, Instead of counting the number of human and horses, he instead counted 74 heads and 196 legs. Yet he knew the number of humans and horses there. How did he do it, and how many humans and horses are there?

Well, horses have 4 legs and humans have two.

It's an algebra problem:

Let h represent the number of humans and e represent the number of horses.
number of heads = h + e = 74
number of legs = 2h + 4e = 196
74 - e = (196 - 4e) / 2 = 98 - 2e
74 - e + 2e = 98
74 + e = 98
e = 98 - 74 = 24
h = 74 - 24 = 50.
So there were 24 horses and 50 humans.

Let's check that. 2*50 = 100. 4*24 = 96. 100 + 96 = 196. My answer is correct.

Create a system of equations:
x + y = 74
2x + 4y = 196

Solve these for x and y, where x represents the number of people, and y represents the number of horses. I would recommend using substitution for this problem.

x = human
y = horses
x+y = 74
2x+4y = 196
2x+2y = 148
2y = 48
y = 24 horses
x = 50 humans