should be used to make the solution?
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Let x = the amount of D5W. (5)
Then 500-x will be the amount of D10W (10)
Find amount of D5W
x(5) + (500 - x)(10) = 500 (8)
5x + 5000 - 10x = 4000
1000 = 5x
x = 200
200ml of D5W
Find amount of D10W
500 - x
500 - 200
=300
300ml of D10W
06162012
Then 500-x will be the amount of D10W (10)
Find amount of D5W
x(5) + (500 - x)(10) = 500 (8)
5x + 5000 - 10x = 4000
1000 = 5x
x = 200
200ml of D5W
Find amount of D10W
500 - x
500 - 200
=300
300ml of D10W
06162012