How do i simplify this

3^√54 / 3^√2

3^√6 / 3^√48

√75 / √3

3√x^12 / 64y^6

I assume that "3^√" means ∛, i.e., cube root.

∛54/∛2 = ∛(27*2)/∛2
  = ∛27 ∛2/∛2
  = ∛(3³)
  = 3


∛6/∛48 = ∛6/∛(8*6)
  = ∛6/[∛8 ∛6]
  = 1/∛(2³)
  = 1/2


√75/√3 = √(25*3)/√3
  = √25 √3/√3
  = √(5²)
  = 5

∛x^12/∛(64y^6) = ∛(x^(4*3)) / ∛(4³ y^(2*3))
  = ∛((x^4)³) / [∛(4³)∛((y²)³)]
  = x^4/(4y²)