Determine an equation of an asymptote of y= sec3x
I have an exam on Monday, and, for the life of me, cannot remember how to do this very basic question.
Explain, please?
Thanks!
I have an exam on Monday, and, for the life of me, cannot remember how to do this very basic question.
Explain, please?
Thanks!
-
y = 1/cos(3x)
cos(3x) = 0
3x = pi/2
x = pi/6 is an asymptote
cos(3x) = 0
3x = pi/2
x = pi/6 is an asymptote